1/2(2y+6)+13=3y

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Solution for 1/2(2y+6)+13=3y equation: 



1/2(2y+6)+13=3y

We move all terms to the left:

1/2(2y+6)+13-(3y)=0



Domain of the equation: 2(2y+6)!=0

y∈R



We add all the numbers together, and all the variables

-3y+1/2(2y+6)+13=0

We multiply all the terms by the denominator


-3y*2(2y+6)+13*2(2y+6)+1=0

Wy multiply elements

-6y^2(2+26y(2+1=0

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