1/2(2y-4)=2+y

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Solution for 1/2(2y-4)=2+y equation: 



1/2(2y-4)=2+y

We move all terms to the left:

1/2(2y-4)-(2+y)=0



Domain of the equation: 2(2y-4)!=0

y∈R



We add all the numbers together, and all the variables

1/2(2y-4)-(y+2)=0

We get rid of parentheses

1/2(2y-4)-y-2=0

We multiply all the terms by the denominator


-y*2(2y-4)-2*2(2y-4)+1=0

Wy multiply elements

-2y^2(2-4y(2+1=0

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