1/2(2z+4)=1/4(z-8)

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Solution for 1/2(2z+4)=1/4(z-8) equation: 



1/2(2z+4)=1/4(z-8)

We move all terms to the left:

1/2(2z+4)-(1/4(z-8))=0



Domain of the equation: 2(2z+4)!=0

z∈R





Domain of the equation: 4(z-8))!=0

z∈R



We calculate fractions


(4zz/(2(2z+4)*4(z-8)))+(-2z2/(2(2z+4)*4(z-8)))=0



We calculate terms in parentheses: +(4zz/(2(2z+4)*4(z-8))), so:

4zz/(2(2z+4)*4(z-8))

We multiply all the terms by the denominator


4zz

Back to the equation:

+(4zz)





We calculate terms in parentheses: +(-2z2/(2(2z+4)*4(z-8))), so:

-2z2/(2(2z+4)*4(z-8))

We multiply all the terms by the denominator


-2z2

We add all the numbers together, and all the variables

-2z^2

Back to the equation:

+(-2z^2)



We get rid of parentheses

-2z^2+4zz=0

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