1/2(35x+35)-2=-1/3(21x-21)

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Solution for 1/2(35x+35)-2=-1/3(21x-21) equation: 



1/2(35x+35)-2=-1/3(21x-21)

We move all terms to the left:

1/2(35x+35)-2-(-1/3(21x-21))=0



Domain of the equation: 2(35x+35)!=0

x∈R





Domain of the equation: 3(21x-21))!=0

x∈R



We calculate fractions


(3x2/(2(35x+35)*3(21x-21)))+(-(-2x3)/(2(35x+35)*3(21x-21)))-2=0



We calculate terms in parentheses: +(3x2/(2(35x+35)*3(21x-21))), so:

3x2/(2(35x+35)*3(21x-21))

We multiply all the terms by the denominator


3x2

We add all the numbers together, and all the variables

3x^2

Back to the equation:

+(3x^2)





We calculate terms in parentheses: +(-(-2x3)/(2(35x+35)*3(21x-21))), so:

-(-2x3)/(2(35x+35)*3(21x-21))

We add all the numbers together, and all the variables

-(-2x^3)/(2(35x+35)*3(21x-21))

We multiply all the terms by the denominator


-(-2x^3)

We do not support expression: x^3

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