1/2(3k-9)=-3/4(2k+11)

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Solution for 1/2(3k-9)=-3/4(2k+11) equation: 



1/2(3k-9)=-3/4(2k+11)

We move all terms to the left:

1/2(3k-9)-(-3/4(2k+11))=0



Domain of the equation: 2(3k-9)!=0

k∈R





Domain of the equation: 4(2k+11))!=0

k∈R



We calculate fractions


(4k2/(2(3k-9)*4(2k+11)))+(-(-6k3)/(2(3k-9)*4(2k+11)))=0



We calculate terms in parentheses: +(4k2/(2(3k-9)*4(2k+11))), so:

4k2/(2(3k-9)*4(2k+11))

We multiply all the terms by the denominator


4k2

We add all the numbers together, and all the variables

4k^2

Back to the equation:

+(4k^2)





We calculate terms in parentheses: +(-(-6k3)/(2(3k-9)*4(2k+11))), so:

-(-6k3)/(2(3k-9)*4(2k+11))

We add all the numbers together, and all the variables

-(-6k^3)/(2(3k-9)*4(2k+11))

We multiply all the terms by the denominator


-(-6k^3)

We do not support ekpression: k^3

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