1/2(3n-4)+3=n+4

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Solution for 1/2(3n-4)+3=n+4 equation: 



1/2(3n-4)+3=n+4

We move all terms to the left:

1/2(3n-4)+3-(n+4)=0



Domain of the equation: 2(3n-4)!=0

n∈R



We get rid of parentheses

1/2(3n-4)-n-4+3=0

We multiply all the terms by the denominator


-n*2(3n-4)-4*2(3n-4)+3*2(3n-4)+1=0

Wy multiply elements

-2n^2(3-8n(3+6n(3+1=0

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