1/2(3n-5)=-13/10(-2n-4)

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Solution for 1/2(3n-5)=-13/10(-2n-4) equation: 



1/2(3n-5)=-13/10(-2n-4)

We move all terms to the left:

1/2(3n-5)-(-13/10(-2n-4))=0



Domain of the equation: 2(3n-5)!=0

n∈R





Domain of the equation: 10(-2n-4))!=0

n∈R



We calculate fractions


(10n(-)/(2(3n-5)*10(-2n-4)))+(-(-26n3)/(2(3n-5)*10(-2n-4)))=0



We calculate terms in parentheses: +(10n(-)/(2(3n-5)*10(-2n-4))), so:

10n(-)/(2(3n-5)*10(-2n-4))

We add all the numbers together, and all the variables

10n0/(2(3n-5)*10(-2n-4))

We multiply all the terms by the denominator


10n0

We add all the numbers together, and all the variables

10n

Back to the equation:

+(10n)





We calculate terms in parentheses: +(-(-26n3)/(2(3n-5)*10(-2n-4))), so:

-(-26n3)/(2(3n-5)*10(-2n-4))

We add all the numbers together, and all the variables

-(-26n^3)/(2(3n-5)*10(-2n-4))

We multiply all the terms by the denominator


-(-26n^3)

We do not support enpression: n^3

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