1/2(3x+2)=2-1/2(x+4)

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Solution for 1/2(3x+2)=2-1/2(x+4) equation:



1/2(3x+2)=2-1/2(x+4)
We move all terms to the left:
1/2(3x+2)-(2-1/2(x+4))=0
Domain of the equation: 2(3x+2)!=0
x∈R
Domain of the equation: 2(x+4))!=0
x∈R
We calculate fractions
(2xx/(2(3x+2)*2(x+4)))+(-(-2x3)/(2(3x+2)*2(x+4)))=0
We calculate terms in parentheses: +(2xx/(2(3x+2)*2(x+4))), so:
2xx/(2(3x+2)*2(x+4))
We multiply all the terms by the denominator
2xx
Back to the equation:
+(2xx)
We calculate terms in parentheses: +(-(-2x3)/(2(3x+2)*2(x+4))), so:
-(-2x3)/(2(3x+2)*2(x+4))
We add all the numbers together, and all the variables
-(-2x^3)/(2(3x+2)*2(x+4))
We multiply all the terms by the denominator
-(-2x^3)
We do not support expression: x^3

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