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1/2(3x+4)=1/2x
We move all terms to the left:
1/2(3x+4)-(1/2x)=0
Domain of the equation: 2(3x+4)!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/2(3x+4)-(+1/2x)=0
We get rid of parentheses
1/2(3x+4)-1/2x=0
We calculate fractions
2x/(12x^2+16x)+(-2x3/(12x^2+16x)=0
We calculate terms in parentheses: +(-2x3/(12x^2+16x), so:
-2x3/(12x^2+16x
We multiply all the terms by the denominator
-2x3
We add all the numbers together, and all the variables
-2x^3
We do not support expression: x^3
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