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1/2(3x+6)=1/3(18x-6)
We move all terms to the left:
1/2(3x+6)-(1/3(18x-6))=0
Domain of the equation: 2(3x+6)!=0
x∈R
Domain of the equation: 3(18x-6))!=0We calculate fractions
x∈R
(3x1/(2(3x+6)*3(18x-6)))+(-2x3/(2(3x+6)*3(18x-6)))=0
We calculate terms in parentheses: +(3x1/(2(3x+6)*3(18x-6))), so:
3x1/(2(3x+6)*3(18x-6))
We multiply all the terms by the denominator
3x1
We add all the numbers together, and all the variables
3x
Back to the equation:
+(3x)
We calculate terms in parentheses: +(-2x3/(2(3x+6)*3(18x-6))), so:
-2x3/(2(3x+6)*3(18x-6))
We multiply all the terms by the denominator
-2x3
We add all the numbers together, and all the variables
-2x^3
We do not support expression: x^3
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