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x in (-oo:+oo)
(1/2)*(3*x-12) = (1/6)*(9*x-6) // - (1/6)*(9*x-6)
(1/2)*(3*x-12)-((1/6)*(9*x-6)) = 0
(1/2)*(3*x-12)+(-1/6)*(9*x-6) = 0
1/2*(3*x-12)-1/6*(9*x-6) = 0
1/2*(3*x-12)-1/6*(9*x-6) = 0
-5 = 0
-5 = 0
x belongs to the empty set
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