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1/2(3x-17)=1/6(8x-10)
We move all terms to the left:
1/2(3x-17)-(1/6(8x-10))=0
Domain of the equation: 2(3x-17)!=0
x∈R
Domain of the equation: 6(8x-10))!=0We calculate fractions
x∈R
(6x8/(2(3x-17)*6(8x-10)))+(-2x3/(2(3x-17)*6(8x-10)))=0
We calculate terms in parentheses: +(6x8/(2(3x-17)*6(8x-10))), so:
6x8/(2(3x-17)*6(8x-10))
We multiply all the terms by the denominator
6x8
We add all the numbers together, and all the variables
6x^8
We do not support expression: x^8
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