1/2(3x-5)+1/3(x-2)=7/2

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Solution for 1/2(3x-5)+1/3(x-2)=7/2 equation: 


x in (-oo:+oo)

(1/2)*(3*x-5)+(1/3)*(x-2) = 7/2 // - 7/2

(1/2)*(3*x-5)+(1/3)*(x-2)-(7/2) = 0

(1/2)*(3*x-5)+(1/3)*(x-2)-7/2 = 0

1/2*(3*x-5)+1/3*(x-2)-7/2 = 0

(1/2*2*(3*x-5))/2+(1/3*2*(x-2))/2-7/2 = 0

1/2*2*(3*x-5)+1/3*2*(x-2)-7 = 0

11/3*x-7-19/3 = 0

11/3*x-40/3 = 0

(11/3*x-40/3)/2 = 0

(11/3*x-40/3)/2 = 0 // * 2

11/3*x-40/3 = 0

11/3*x-40/3 = 0 // + 40/3

11/3*x = 40/3 // : 11/3

x = 40/3/11/3

x = 40/11

x = 40/11

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