1/2(3x-5)=6x+-10

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Solution for 1/2(3x-5)=6x+-10 equation: 



1/2(3x-5)=6x+-10

We move all terms to the left:

1/2(3x-5)-(6x+-10)=0



Domain of the equation: 2(3x-5)!=0

x∈R



We add all the numbers together, and all the variables

1/2(3x-5)-(6x-10)=0

We get rid of parentheses

1/2(3x-5)-6x+10=0

We multiply all the terms by the denominator


-6x*2(3x-5)+10*2(3x-5)+1=0

Wy multiply elements

-12x^2(3+20x(3+1=0

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