1/2(3x-8)=4/5(x+2)

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Solution for 1/2(3x-8)=4/5(x+2) equation: 



1/2(3x-8)=4/5(x+2)

We move all terms to the left:

1/2(3x-8)-(4/5(x+2))=0



Domain of the equation: 2(3x-8)!=0

x∈R





Domain of the equation: 5(x+2))!=0

x∈R



We calculate fractions


(5xx/(2(3x-8)*5(x+2)))+(-8x3/(2(3x-8)*5(x+2)))=0



We calculate terms in parentheses: +(5xx/(2(3x-8)*5(x+2))), so:

5xx/(2(3x-8)*5(x+2))

We multiply all the terms by the denominator


5xx

Back to the equation:

+(5xx)





We calculate terms in parentheses: +(-8x3/(2(3x-8)*5(x+2))), so:

-8x3/(2(3x-8)*5(x+2))

We multiply all the terms by the denominator


-8x3

We add all the numbers together, and all the variables

-8x^3

We do not support expression: x^3

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