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1/2(3y+5)=2/3(2y-1)
We move all terms to the left:
1/2(3y+5)-(2/3(2y-1))=0
Domain of the equation: 2(3y+5)!=0
y∈R
Domain of the equation: 3(2y-1))!=0We calculate fractions
y∈R
(3y2/(2(3y+5)*3(2y-1)))+(-4y3/(2(3y+5)*3(2y-1)))=0
We calculate terms in parentheses: +(3y2/(2(3y+5)*3(2y-1))), so:
3y2/(2(3y+5)*3(2y-1))
We multiply all the terms by the denominator
3y2
We add all the numbers together, and all the variables
3y^2
Back to the equation:
+(3y^2)
We calculate terms in parentheses: +(-4y3/(2(3y+5)*3(2y-1))), so:
-4y3/(2(3y+5)*3(2y-1))
We multiply all the terms by the denominator
-4y3
We add all the numbers together, and all the variables
-4y^3
We do not support eypression: y^3
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