1/2(3y+5)=2/3(2y-1)

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Solution for 1/2(3y+5)=2/3(2y-1) equation: 



1/2(3y+5)=2/3(2y-1)

We move all terms to the left:

1/2(3y+5)-(2/3(2y-1))=0



Domain of the equation: 2(3y+5)!=0

y∈R





Domain of the equation: 3(2y-1))!=0

y∈R



We calculate fractions


(3y2/(2(3y+5)*3(2y-1)))+(-4y3/(2(3y+5)*3(2y-1)))=0



We calculate terms in parentheses: +(3y2/(2(3y+5)*3(2y-1))), so:

3y2/(2(3y+5)*3(2y-1))

We multiply all the terms by the denominator


3y2

We add all the numbers together, and all the variables

3y^2

Back to the equation:

+(3y^2)





We calculate terms in parentheses: +(-4y3/(2(3y+5)*3(2y-1))), so:

-4y3/(2(3y+5)*3(2y-1))

We multiply all the terms by the denominator


-4y3

We add all the numbers together, and all the variables

-4y^3

We do not support eypression: y^3

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