1/2(3y-8)+10-7/2y=16

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Solution for 1/2(3y-8)+10-7/2y=16 equation: 



1/2(3y-8)+10-7/2y=16

We move all terms to the left:

1/2(3y-8)+10-7/2y-(16)=0



Domain of the equation: 2(3y-8)!=0

y∈R





Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R



We add all the numbers together, and all the variables

1/2(3y-8)-7/2y-6=0

We calculate fractions


2y/(12y^2-32y)+(-14y3/(12y^2-32y)-6=0

We calculate fractions

We do not support eypression: y^3

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