1/2(4-4x)=2/5(5-10x)

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Solution for 1/2(4-4x)=2/5(5-10x) equation: 



1/2(4-4x)=2/5(5-10x)

We move all terms to the left:

1/2(4-4x)-(2/5(5-10x))=0



Domain of the equation: 2(4-4x)!=0

x∈R





Domain of the equation: 5(5-10x))!=0

x∈R



We add all the numbers together, and all the variables

1/2(-4x+4)-(2/5(-10x+5))=0

We calculate fractions


(5x(-)/(2(-4x+4)*5(-10x+5)))+(-4x0/(2(-4x+4)*5(-10x+5)))=0



We calculate terms in parentheses: +(5x(-)/(2(-4x+4)*5(-10x+5))), so:

5x(-)/(2(-4x+4)*5(-10x+5))

We add all the numbers together, and all the variables

5x0/(2(-4x+4)*5(-10x+5))

We multiply all the terms by the denominator


5x0

We add all the numbers together, and all the variables

5x

Back to the equation:

+(5x)





We calculate terms in parentheses: +(-4x0/(2(-4x+4)*5(-10x+5))), so:

-4x0/(2(-4x+4)*5(-10x+5))

We multiply all the terms by the denominator


-4x0

We add all the numbers together, and all the variables

-4x

Back to the equation:

+(-4x)



We get rid of parentheses

5x-4x=0

We add all the numbers together, and all the variables

x=0

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