1/2(4-z)=1/2(4-z)

Solution for 1/2(4-z)=1/2(4-z) equation:

1/2(4-z)=1/2(4-z)

We move all terms to the left:

1/2(4-z)-(1/2(4-z))=0


Domain of the equation: 2(4-z)!=0

z∈R



Domain of the equation: 2(4-z))!=0

z∈R


We add all the numbers together, and all the variables

1/2(-1z+4)-(1/2(-1z+4))=0

We calculate fractions


(2z(-)/(2(-1z+4)*2(-1z+4)))+(-2z0/(2(-1z+4)*2(-1z+4)))=0


We calculate terms in parentheses: +(2z(-)/(2(-1z+4)*2(-1z+4))), so:

2z(-)/(2(-1z+4)*2(-1z+4))

We add all the numbers together, and all the variables

2z0/(2(-1z+4)*2(-1z+4))

We multiply all the terms by the denominator


2z0

We add all the numbers together, and all the variables

2z

Back to the equation:

+(2z)



We calculate terms in parentheses: +(-2z0/(2(-1z+4)*2(-1z+4))), so:

-2z0/(2(-1z+4)*2(-1z+4))

We multiply all the terms by the denominator


-2z0

We add all the numbers together, and all the variables

-2z

Back to the equation:

+(-2z)


We get rid of parentheses

2z-2z=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0