1/2(4-z)=2-0.5z

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Solution for 1/2(4-z)=2-0.5z equation: 



1/2(4-z)=2-0.5z

We move all terms to the left:

1/2(4-z)-(2-0.5z)=0



Domain of the equation: 2(4-z)!=0

z∈R



We add all the numbers together, and all the variables

1/2(-1z+4)-(-0.5z+2)=0

We get rid of parentheses

1/2(-1z+4)+0.5z-2=0

We multiply all the terms by the denominator


(0.5z)*2(-1z+4)-2*2(-1z+4)+1=0

We add all the numbers together, and all the variables

(+0.5z)*2(-1z+4)-2*2(-1z+4)+1=0

Wy multiply elements

(+0.5z)*2(-1z+4)-4z(-+1=0

We use the square of the difference formula

(+0.5z)*2(-1z+4)-4z(-1=0

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