1/2(40-8x)=19+2-5x

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Solution for 1/2(40-8x)=19+2-5x equation: 



1/2(40-8x)=19+2-5x

We move all terms to the left:

1/2(40-8x)-(19+2-5x)=0



Domain of the equation: 2(40-8x)!=0

x∈R



We add all the numbers together, and all the variables

1/2(-8x+40)-(-5x+21)=0

We get rid of parentheses

1/2(-8x+40)+5x-21=0

We multiply all the terms by the denominator


5x*2(-8x+40)-21*2(-8x+40)+1=0

Wy multiply elements

10x^2(--42x(-+1=0

We use the square of the difference formula

10x^2(+42x(-1=0

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