1/2(4b+2)-5=5b-4-3b

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Solution for 1/2(4b+2)-5=5b-4-3b equation: 



1/2(4b+2)-5=5b-4-3b

We move all terms to the left:

1/2(4b+2)-5-(5b-4-3b)=0



Domain of the equation: 2(4b+2)!=0

b∈R



We add all the numbers together, and all the variables

1/2(4b+2)-(2b-4)-5=0

We get rid of parentheses

1/2(4b+2)-2b+4-5=0

We multiply all the terms by the denominator


-2b*2(4b+2)+4*2(4b+2)-5*2(4b+2)+1=0

Wy multiply elements

-4b^2(4+8b(4-10b(4+1=0

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