1/2(4b+2)=7-1/4(8b-4)

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Solution for 1/2(4b+2)=7-1/4(8b-4) equation: 



1/2(4b+2)=7-1/4(8b-4)

We move all terms to the left:

1/2(4b+2)-(7-1/4(8b-4))=0



Domain of the equation: 2(4b+2)!=0

b∈R





Domain of the equation: 4(8b-4))!=0

b∈R



We calculate fractions


(4b8/(2(4b+2)*4(8b-4)))+(-(-2b4)/(2(4b+2)*4(8b-4)))=0



We calculate terms in parentheses: +(4b8/(2(4b+2)*4(8b-4))), so:

4b8/(2(4b+2)*4(8b-4))

We multiply all the terms by the denominator


4b8

We add all the numbers together, and all the variables

4b^8

We do not support ebpression: b^8

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