1/2(4c-18)=6

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Solution for 1/2(4c-18)=6 equation: 



1/2(4c-18)=6

We move all terms to the left:

1/2(4c-18)-(6)=0



Domain of the equation: 2(4c-18)!=0

c∈R



We multiply all the terms by the denominator


-6*2(4c-18)+1=0

Wy multiply elements

-12c(4+1=0

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