1/2(4d-2d)=d+5

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Solution for 1/2(4d-2d)=d+5 equation: 


d in (-oo:+oo)

(1/2)*(4*d-(2*d)) = d+5 // - d+5

(1/2)*(4*d-(2*d))-d-5 = 0

(1/2)*(4*d-2*d)-d-5 = 0

1/2*2*d-d-5 = 0

1/2*2*d-d-5 = 0

-5 = 0

-5 = 0

d belongs to the empty set

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