1/2(4e-16)=1/3(3e+6)

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Solution for 1/2(4e-16)=1/3(3e+6) equation: 



1/2(4e-16)=1/3(3e+6)

We move all terms to the left:

1/2(4e-16)-(1/3(3e+6))=0



Domain of the equation: 2(4e-16)!=0

e∈R





Domain of the equation: 3(3e+6))!=0

e∈R



We calculate fractions


(3e3/(2(4e-16)*3(3e+6)))+(-2e4/(2(4e-16)*3(3e+6)))=0



We calculate terms in parentheses: +(3e3/(2(4e-16)*3(3e+6))), so:

3e3/(2(4e-16)*3(3e+6))

We multiply all the terms by the denominator


3e3

We add all the numbers together, and all the variables

3e^3

We do not support eepression: e^3

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