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1/2(4k+2)-5k=10
We move all terms to the left:
1/2(4k+2)-5k-(10)=0
Domain of the equation: 2(4k+2)!=0We add all the numbers together, and all the variables
k∈R
-5k+1/2(4k+2)-10=0
We multiply all the terms by the denominator
-5k*2(4k+2)-10*2(4k+2)+1=0
Wy multiply elements
-10k^2(4-20k(4+1=0
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