1/2(4m-18=15

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Solution for 1/2(4m-18=15 equation: 



1/2(4m-18=15

We move all terms to the left:

1/2(4m-18-(15)=0



Domain of the equation: 2(4m-18-15!=0

m∈R



We multiply all the terms by the denominator


1!=0

There is no solution for this equation

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