1/2(4w+4)+4(w+2)=40

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Solution for 1/2(4w+4)+4(w+2)=40 equation: 



1/2(4w+4)+4(w+2)=40

We move all terms to the left:

1/2(4w+4)+4(w+2)-(40)=0



Domain of the equation: 2(4w+4)!=0

w∈R



We multiply parentheses

1/2(4w+4)+4w+8-40=0

We multiply all the terms by the denominator


4w*2(4w+4)+8*2(4w+4)-40*2(4w+4)+1=0

Wy multiply elements

8w^2(4+16w(4-80w(4+1=0

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