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1/2(4x*8)=3/4(12x+16)
We move all terms to the left:
1/2(4x*8)-(3/4(12x+16))=0
Domain of the equation: 2(4x*8)!=0
x∈R
Domain of the equation: 4(12x+16))!=0We add all the numbers together, and all the variables
x∈R
1/2(+4x*8)-(3/4(12x+16))=0
We calculate fractions
(4x1/(2(+4x*8)*4(12x+16)))+(-48x0/(2(+4x*8)*4(12x+16)))=0
We calculate terms in parentheses: +(4x1/(2(+4x*8)*4(12x+16))), so:
4x1/(2(+4x*8)*4(12x+16))
We multiply all the terms by the denominator
4x1
We add all the numbers together, and all the variables
4x
Back to the equation:
+(4x)
We calculate terms in parentheses: +(-48x0/(2(+4x*8)*4(12x+16))), so:We get rid of parentheses
-48x0/(2(+4x*8)*4(12x+16))
We multiply all the terms by the denominator
-48x0
We add all the numbers together, and all the variables
-48x
Back to the equation:
+(-48x)
4x-48x=0
We add all the numbers together, and all the variables
-44x=0
x=0/-44
x=0
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