1/2(4x+12)=1/4(4x-8)=1/3(9x+27)

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Solution for 1/2(4x+12)=1/4(4x-8)=1/3(9x+27) equation: 



1/2(4x+12)=1/4(4x-8)=1/3(9x+27)

We move all terms to the left:

1/2(4x+12)-(1/4(4x-8))=0



Domain of the equation: 2(4x+12)!=0

x∈R





Domain of the equation: 4(4x-8))!=0

x∈R



We calculate fractions


(4x4/(2(4x+12)*4(4x-8)))+(-2x4/(2(4x+12)*4(4x-8)))=0



We calculate terms in parentheses: +(4x4/(2(4x+12)*4(4x-8))), so:

4x4/(2(4x+12)*4(4x-8))

We multiply all the terms by the denominator


4x4

We add all the numbers together, and all the variables

4x^4

We do not support expression: x^4

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