1/2(4x+12)=2(x+3)

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Solution for 1/2(4x+12)=2(x+3) equation: 



1/2(4x+12)=2(x+3)

We move all terms to the left:

1/2(4x+12)-(2(x+3))=0



Domain of the equation: 2(4x+12)!=0

x∈R



We multiply all the terms by the denominator


-((2(x+3)))*2(4x+12)+1=0



We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





We calculate terms in parentheses: -((2(x+3)))*2(4x+12), so:

(2(x+3)))*2(4x+12





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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