1/2(4x+16)-6=-2/3(2x-9)

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Solution for 1/2(4x+16)-6=-2/3(2x-9) equation: 



1/2(4x+16)-6=-2/3(2x-9)

We move all terms to the left:

1/2(4x+16)-6-(-2/3(2x-9))=0



Domain of the equation: 2(4x+16)!=0

x∈R





Domain of the equation: 3(2x-9))!=0

x∈R



We calculate fractions


(3x2/(2(4x+16)*3(2x-9)))+(-(-4x4)/(2(4x+16)*3(2x-9)))-6=0



We calculate terms in parentheses: +(3x2/(2(4x+16)*3(2x-9))), so:

3x2/(2(4x+16)*3(2x-9))

We multiply all the terms by the denominator


3x2

We add all the numbers together, and all the variables

3x^2

Back to the equation:

+(3x^2)





We calculate terms in parentheses: +(-(-4x4)/(2(4x+16)*3(2x-9))), so:

-(-4x4)/(2(4x+16)*3(2x-9))

We add all the numbers together, and all the variables

-(-4x^4)/(2(4x+16)*3(2x-9))

We multiply all the terms by the denominator


-(-4x^4)

We do not support expression: x^4

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