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1/2(4x+5)=9x-12(x-
We move all terms to the left:
1/2(4x+5)-(9x-12(x-)=0
Domain of the equation: 2(4x+5)!=0We add all the numbers together, and all the variables
x∈R
1/2(4x+5)-(9x-12(+x)=0
We multiply all the terms by the denominator
-((9x-12(+x))*2(4x+5)+1=0
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