1/2(4x+8)=-1/2(-6x-12)

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Solution for 1/2(4x+8)=-1/2(-6x-12) equation: 



1/2(4x+8)=-1/2(-6x-12)

We move all terms to the left:

1/2(4x+8)-(-1/2(-6x-12))=0



Domain of the equation: 2(4x+8)!=0

x∈R





Domain of the equation: 2(-6x-12))!=0

x∈R



We calculate fractions


(2x(-)/(2(4x+8)*2(-6x-12)))+(-(-2x4)/(2(4x+8)*2(-6x-12)))=0



We calculate terms in parentheses: +(2x(-)/(2(4x+8)*2(-6x-12))), so:

2x(-)/(2(4x+8)*2(-6x-12))

We add all the numbers together, and all the variables

2x0/(2(4x+8)*2(-6x-12))

We multiply all the terms by the denominator


2x0

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)





We calculate terms in parentheses: +(-(-2x4)/(2(4x+8)*2(-6x-12))), so:

-(-2x4)/(2(4x+8)*2(-6x-12))

We add all the numbers together, and all the variables

-(-2x^4)/(2(4x+8)*2(-6x-12))

We multiply all the terms by the denominator


-(-2x^4)

We do not support expression: x^4

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