1/2(4x-)+3x=6x-10

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Solution for 1/2(4x-)+3x=6x-10 equation:



1/2(4x-)+3x=6x-10
We move all terms to the left:
1/2(4x-)+3x-(6x-10)=0
Domain of the equation: 2(4x-)!=0
x∈R
We add all the numbers together, and all the variables
1/2(+4x)+3x-(6x-10)=0
We add all the numbers together, and all the variables
3x+1/2(+4x)-(6x-10)=0
We get rid of parentheses
3x+1/2(+4x)-6x+10=0
We multiply all the terms by the denominator
3x*2(+4x)-6x*2(+4x)+10*2(+4x)+1=0
Wy multiply elements
6x^2(+-12x^2(++20x(++1=0
We use the square of the difference formula
6x^2(-12x^2(+20x(+1=0

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