1/2(4x-10)=1/4(6x+28)

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Solution for 1/2(4x-10)=1/4(6x+28) equation: 



1/2(4x-10)=1/4(6x+28)

We move all terms to the left:

1/2(4x-10)-(1/4(6x+28))=0



Domain of the equation: 2(4x-10)!=0

x∈R





Domain of the equation: 4(6x+28))!=0

x∈R



We calculate fractions


(4x6/(2(4x-10)*4(6x+28)))+(-2x4/(2(4x-10)*4(6x+28)))=0



We calculate terms in parentheses: +(4x6/(2(4x-10)*4(6x+28))), so:

4x6/(2(4x-10)*4(6x+28))

We multiply all the terms by the denominator


4x6

We add all the numbers together, and all the variables

4x^6

We do not support expression: x^6

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