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1/2(4x-2)-2(3x+3)=9+2(x+4)
We move all terms to the left:
1/2(4x-2)-2(3x+3)-(9+2(x+4))=0
Domain of the equation: 2(4x-2)!=0We multiply parentheses
x∈R
1/2(4x-2)-6x-(9+2(x+4))-6=0
We multiply all the terms by the denominator
-6x*2(4x-2)-((9+2(x+4)))*2(4x-2)-6*2(4x-2)+1=0
We calculate terms in parentheses: -((9+2(x+4)))*2(4x-2), so:Wy multiply elements
(9+2(x+4)))*2(4x-2
-12x^2(4-((9+2(x+4)))*2(4x-2)-12x(4+1=0
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