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1/2(4x-4)=5x+10+x
We move all terms to the left:
1/2(4x-4)-(5x+10+x)=0
Domain of the equation: 2(4x-4)!=0We add all the numbers together, and all the variables
x∈R
1/2(4x-4)-(6x+10)=0
We get rid of parentheses
1/2(4x-4)-6x-10=0
We multiply all the terms by the denominator
-6x*2(4x-4)-10*2(4x-4)+1=0
Wy multiply elements
-12x^2(4-20x(4+1=0
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