1/2(4y+12)=10

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Solution for 1/2(4y+12)=10 equation: 



1/2(4y+12)=10

We move all terms to the left:

1/2(4y+12)-(10)=0



Domain of the equation: 2(4y+12)!=0

y∈R



We multiply all the terms by the denominator


-10*2(4y+12)+1=0

Wy multiply elements

-20y(4+1=0

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