1/2(4y+26)=1/5(25y-15)

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Solution for 1/2(4y+26)=1/5(25y-15) equation: 



1/2(4y+26)=1/5(25y-15)

We move all terms to the left:

1/2(4y+26)-(1/5(25y-15))=0



Domain of the equation: 2(4y+26)!=0

y∈R





Domain of the equation: 5(25y-15))!=0

y∈R



We calculate fractions


(5y2/(2(4y+26)*5(25y-15)))+(-2y4/(2(4y+26)*5(25y-15)))=0



We calculate terms in parentheses: +(5y2/(2(4y+26)*5(25y-15))), so:

5y2/(2(4y+26)*5(25y-15))

We multiply all the terms by the denominator


5y2

We add all the numbers together, and all the variables

5y^2

Back to the equation:

+(5y^2)





We calculate terms in parentheses: +(-2y4/(2(4y+26)*5(25y-15))), so:

-2y4/(2(4y+26)*5(25y-15))

We multiply all the terms by the denominator


-2y4

We add all the numbers together, and all the variables

-2y^4

We do not support eypression: y^4

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