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1/2(5-2h)=h
We move all terms to the left:
1/2(5-2h)-(h)=0
Domain of the equation: 2(5-2h)!=0We add all the numbers together, and all the variables
h∈R
1/2(-2h+5)-h=0
We add all the numbers together, and all the variables
-1h+1/2(-2h+5)=0
We multiply all the terms by the denominator
-1h*2(-2h+5)+1=0
Wy multiply elements
-2h^2(-+1=0
We use the square of the difference formula
-2h^2(-1=0
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