1/2(5-3t)=5/6(t-2)

Solution for 1/2(5-3t)=5/6(t-2) equation:

1/2(5-3t)=5/6(t-2)

We move all terms to the left:

1/2(5-3t)-(5/6(t-2))=0


Domain of the equation: 2(5-3t)!=0

t∈R



Domain of the equation: 6(t-2))!=0

t∈R


We add all the numbers together, and all the variables

1/2(-3t+5)-(5/6(t-2))=0

We calculate fractions


(6tt/(2(-3t+5)*6(t-2)))+(-10t0/(2(-3t+5)*6(t-2)))=0


We calculate terms in parentheses: +(6tt/(2(-3t+5)*6(t-2))), so:

6tt/(2(-3t+5)*6(t-2))

We multiply all the terms by the denominator


6tt

Back to the equation:

+(6tt)



We calculate terms in parentheses: +(-10t0/(2(-3t+5)*6(t-2))), so:

-10t0/(2(-3t+5)*6(t-2))

We multiply all the terms by the denominator


-10t0

We add all the numbers together, and all the variables

-10t

Back to the equation:

+(-10t)


We get rid of parentheses

6tt-10t=0

We add all the numbers together, and all the variables

-10t+6tt=0