If it's not what You are looking for type in the equation solver your own equation and let us solve it.
X in (-oo:+oo)
(1/2)*(5*X-12) = 0
1/2*(5*X-12) = 0
( 1/2 )
1/2 = 0
X belongs to the empty set
( 5*X-12 )
5*X-12 = 0 // + 12
5*X = 12 // : 5
X = 12/5
X = 12/5
| 27-6y-9=17y-9-2y | | 1+3*5= | | a=-8+7 | | -97=-16x^2+41x | | 5+(x-11)=x-14 | | (10/4-5x)-(5/5x-4) | | 10/4-5x-5/5x-4 | | -t^2+7t-10=2 | | 2x+y=3x-2y | | 60=-2y+60 | | 12ux^2y^6-18u^4x^9= | | -5-v=1/3 | | 2xsquared-9=-1 | | 6p+20=-3(1.5-4p) | | 0.5=-5t^2+15t | | 6x+3y-x-8y= | | 3x+4x+8=0 | | (4+8)(3y-2)=0 | | .12x+.13y= | | 3.45+m=9.45 | | 2t-3=2 | | 6n+2=30-10 | | 7x-5-3x=35 | | 11x+5y=13 | | .12x+.13y=190 | | 6y+4=8+2x+2y | | 2x+7x-74x+9= | | 6(4x)-6(5x)=6 | | 4x^7-10x^5+6x^4= | | (x+6)(x+14)=57 | | 4(x+2)=58-3x | | 2b^5c/7c^4x14c/b^4 |