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1/2(5b+3)=3b-2
We move all terms to the left:
1/2(5b+3)-(3b-2)=0
Domain of the equation: 2(5b+3)!=0We get rid of parentheses
b∈R
1/2(5b+3)-3b+2=0
We multiply all the terms by the denominator
-3b*2(5b+3)+2*2(5b+3)+1=0
Wy multiply elements
-6b^2(5+4b(5+1=0
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