1/2(5x-2,5)+25=1/4(x-16)

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Solution for 1/2(5x-2,5)+25=1/4(x-16) equation: 



1/2(5x-2.5)+25=1/4(x-16)

We move all terms to the left:

1/2(5x-2.5)+25-(1/4(x-16))=0



Domain of the equation: 2(5x-2.5)!=0

x∈R





Domain of the equation: 4(x-16))!=0

x∈R



We calculate fractions


(4xx/(2(5x-2.5)*4(x-16)))+(-2x5/(2(5x-2.5)*4(x-16)))+25=0



We calculate terms in parentheses: +(4xx/(2(5x-2.5)*4(x-16))), so:

4xx/(2(5x-2.5)*4(x-16))

We multiply all the terms by the denominator


4xx

Back to the equation:

+(4xx)





We calculate terms in parentheses: +(-2x5/(2(5x-2.5)*4(x-16))), so:

-2x5/(2(5x-2.5)*4(x-16))

We multiply all the terms by the denominator


-2x5

We add all the numbers together, and all the variables

-2x^5

We do not support expression: x^5

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