1/2(5x-3)+7/4=x/2

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Solution for 1/2(5x-3)+7/4=x/2 equation: 


x in (-oo:+oo)

(1/2)*(5*x-3)+7/4 = x/2 // - x/2

(1/2)*(5*x-3)-(x/2)+7/4 = 0

1/2*(5*x-3)-x/2+7/4 = 0

(1/2*2*4*(5*x-3))/(2*4)+(4*(-x))/(2*4)+(2*7)/(2*4) = 0

1/2*2*4*(5*x-3)+4*(-x)+2*7 = 0

16*x-12+14 = 0

16*x+2 = 0

(16*x+2)/(2*4) = 0

(16*x+2)/(2*4) = 0 // * 2*4

16*x+2 = 0

16*x+2 = 0 // - 2

16*x = -2 // : 16

x = -2/16

x = -1/8

x = -1/8

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