1/2(5y+4)=1/3(2y-1)

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Solution for 1/2(5y+4)=1/3(2y-1) equation: 



1/2(5y+4)=1/3(2y-1)

We move all terms to the left:

1/2(5y+4)-(1/3(2y-1))=0



Domain of the equation: 2(5y+4)!=0

y∈R





Domain of the equation: 3(2y-1))!=0

y∈R



We calculate fractions


(3y2/(2(5y+4)*3(2y-1)))+(-2y5/(2(5y+4)*3(2y-1)))=0



We calculate terms in parentheses: +(3y2/(2(5y+4)*3(2y-1))), so:

3y2/(2(5y+4)*3(2y-1))

We multiply all the terms by the denominator


3y2

We add all the numbers together, and all the variables

3y^2

Back to the equation:

+(3y^2)





We calculate terms in parentheses: +(-2y5/(2(5y+4)*3(2y-1))), so:

-2y5/(2(5y+4)*3(2y-1))

We multiply all the terms by the denominator


-2y5

We add all the numbers together, and all the variables

-2y^5

We do not support eypression: y^5

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