1/2(6+-z)=z

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Solution for 1/2(6+-z)=z equation: 



1/2(6+-z)=z

We move all terms to the left:

1/2(6+-z)-(z)=0



Domain of the equation: 2(6+-z)!=0

z∈R



We add all the numbers together, and all the variables

1/2(-1z)-z=0

We add all the numbers together, and all the variables

-1z+1/2(-1z)=0

We multiply all the terms by the denominator


-1z*2(-1z)+1=0

Wy multiply elements

-2z^2(-+1=0

We use the square of the difference formula

-2z^2(-1=0

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