1/2(6+2)-x=x+-1/2(6+2)

Solution for 1/2(6+2)-x=x+-1/2(6+2) equation:

1/2(6+2)-x=x+-1/2(6+2)

We move all terms to the left:

1/2(6+2)-x-(x+-1/2(6+2))=0

We add all the numbers together, and all the variables

-x-(x+-1/28)+1/28=0

We add all the numbers together, and all the variables

-1x-(x+-1/28)+1/28=0

We use the square of the difference formula

-1x-(x-1/28)+1/28=0

We get rid of parentheses

-1x-x+1/28+1/28=0

We multiply all the terms by the denominator


-1x*28-x*28+1+1=0

We add all the numbers together, and all the variables

-1x*28-x*28+2=0

Wy multiply elements

-28x-28x+2=0

We add all the numbers together, and all the variables

-56x+2=0

We move all terms containing x to the left, all other terms to the right

-56x=-2

x=-2/-56

x=1/28